Foye Oluokun got named the AFC defensive player of the week, and honestly, it’s about time someone recognized that dude’s work after what he pulled last Sunday. The Jaguars have been on an impressive roll to start the season, and Oluokun was absolutely integral to their 22-17 win against the Bengals.
Oluokun Shut Down the Bengals When It Mattered Most
Talk about stepping up in a crucial moment! Oluokun delivered seven tackles, a massive interception, a forced fumble, and even a quarterback hit against the Bengals. That pick was absolutely wild, coming early in the fourth quarter at Jacksonville’s own 10-yard line. Imagine the pressure, man. He just snuffed out a potential Bengals score and kept the Jags up 16-10 heading into those nail-biting final minutes. That’s the kind of play that shifts momentum and saves games.
Another One For The Trophy Case
The NFL officially handed Oluokun the AFC defensive player of the week honors on Wednesday. This ain’t his first rodeo, either. This is the fourth time the guy has snagged conference player of the week honors in his career. The first two times he earned the award were back when he was with the Falcons, and now he’s grabbed two more since moving on to the Jaguars. He’s a consistent force, plain and simple.
What a performance, right? Foye Oluokun is a legit problem for opposing offenses. He just keeps making plays that directly impact the scoreboard. You gotta respect that kind of consistent, game-changing production week in and week out.
This article was created with AI assistance and published under Seattle On Tap’s editorial standards. See our Editorial Policy.
Originally reported by Pro Football Talk.
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